[SQL]实现按照指定分割分分割字符串

SET QUOTED_IDENTIFIER ON
SET ANSI_NULLS ON
GO
CREATE function [dbo].[fun_split](@SourceSql varchar(max),@StrSeprate varchar(10))
returns @temp table(SplitValue NVARCHAR(max))
--功能: 实现split的函数
--用法：select * from dbo.fun_split('ABC:BC:C:D:E::',':')
as
begin
declare @i int
set @SourceSql=rtrim(ltrim(@SourceSql))
set @i=charindex(@StrSeprate,@SourceSql)
while @i>=1
begin
insert @temp values(left(@SourceSql,@i-1))
set @SourceSql=substring(@SourceSql,@i+1,len(@SourceSql)-@i)
set @i=charindex(@StrSeprate,@SourceSql)
end
if @SourceSql<>'\'
insert @temp values(@SourceSql)
return
end
GO