您的位置:首页 > 编程语言 > C语言/C++

缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int---->解决方法

2012-11-28 19:21 1671 查看
写了一个对应让其出的错误(其实也挺不容易的喔 )
错误如下:
1>d:\work\win32project\testeachotherclude\testeachotherclude\test2.h(9): error C2143: 语法错误 : 缺少“;”(在“*”的前面)
1>d:\work\win32project\testeachotherclude\testeachotherclude\test2.h(9): error C4430: 缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int
1>d:\work\win32project\testeachotherclude\testeachotherclude\test2.h(9): error C4430: 缺少类型说明符 - 假定为 int。注意: C++ 不支持默认 int
1>d:\work\win32project\testeachotherclude\testeachotherclude\test2.h(10): error C2061: 语法错误: 标识符“Test1”
1>d:\work\win32project\testeachotherclude\testeachotherclude\testeachotherclude.cpp(15): error C2660: “Test2::className”: 函数不接受 1 个参数
1>d:\work\win32project\testeachotherclude\testeachotherclude\testeachotherclude.cpp(16): error C2039: “test1”: 不是“Test2”的成员
1> d:\work\win32project\testeachotherclude\testeachotherclude\test2.h(7) : 参见“Test2”的声明
1>d:\work\win32project\testeachotherclude\testeachotherclude\testeachotherclude.cpp(16): error C2227: “->refMe”的左边必须指向类/结构/联合/泛型类型
上传Test方便大家看:
main.cpp
#include "stdafx.h"
#include "Test1.h"
#include "Test2.h"

int _tmain(int argc, _TCHAR* argv[])
{
	Test1* t1=new Test1();
	Test2* t2=new Test2();
	t1->className(t2);
	t1->test2->refMe();

	t2->className(t1);
	t2->test1->refMe();
	return 0;
}
再来看Test1的
Test1.h
#ifndef Test1_H
#define Test1_H

#include "Test2.h"

class Test1
{
public:
	Test2* test2;
	void Test1::className(Test2* test2);
	void refMe();
};
#endif;
Test1.cpp
#include "Test2.h"

void Test1::className(Test2* test2)
{
	this->test2=test2;
	std::cout<<"Test1  ";
}

void Test1::refMe()
{
	std::cout<<"refMe Test1"<<std::endl;
}
Test2.h
#ifndef Test2_H
#define Test2_H

#include "Test1.h"

class Test2
{
public:
	Test1* test1;
	void className(Test1* test1);
	void refMe();
};
#endif
Test2.cpp
#include "StdAfx.h"
#include "Test2.h"
#include <iostream>

void Test2::className(Test1* test1)
{
	this->test1=test1;
	std::cout<<"Test2  ";
}

void Test2::refMe()
{
	std::cout<<"refMe Test2"<<std::endl;
}

然后运行就报上面的一对错误了...
仔细看看发现两个头文件都彼此包含了,就是这个问题啦...那我们怎么解决了,上传我的代码,直接看这样更容易理解 main.cpp不变
Test1.h
#ifndef Test1_H
#define Test1_H
//#include "Test2.h" //用下面的方式替代
class Test2;//注意:只是告诉编译器,需要这个类,其他功能结构等都没

class Test1
{
public:
	Test2* test2;
	void Test1::className(Test2* test2);
	void refMe();
};
#endif;

Test1.cpp
#include "StdAfx.h"
#include "Test1.h"
#include <iostream>

#include "Test2.h" //注意:这里才是真正的包含

void Test1::className(Test2* test2)
{
	this->test2=test2;
	std::cout<<"Test1  ";
}

void Test1::refMe()
{
	std::cout<<"refMe Test1"<<std::endl;
}

Tes2的我就不贴了,一样的道理,编译运行ok ....

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: 
相关文章推荐