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struts2 session 1(通过ActionContext class中的方法getSession得到)

2012-09-19 17:23 417 查看

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 
<display-name>StrutsTutorial</display-name>

<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>

<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>

struts.xml

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>
<package name="login" extends="struts-default">
<action name="test" class="action.TestAction">
<result name="success">/show.jsp</result>
</action>
</package>
</struts>

java

package action;

import java.util.Map;

import com.opensymphony.xwork2.ActionContext;
import com.opensymphony.xwork2.ActionSupport;

public class TestAction extends ActionSupport{

@Override
public String execute()
{
ActionContext actionContext = ActionContext.getContext();
Map session = actionContext.getSession();
session.put("USER_NAME", "Test User");
return SUCCESS;
}

}

jsp

<%@ page contentType="text/html; charset=utf-8" language="java"%>
<%@taglib prefix="s" uri="/struts-tags"%>
<html>
<head>
</head>
<body>
<s:property value="#session.USER_NAME"/>
</body>
</html>

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