用C#统计未排序一维数组中重复元素的个数

int[] data = new int[50];//用于存储整形数据
string input = "";
int amount = 0;//存储输入数据的个数
int temp1 = 0, temp2 = 0;
int k = 0;//计数临时变量，用于统计数据的二维数组
//输入数据
Console.WriteLine("请输入一组整形数据");
input = Console.ReadLine();
while (!input.Equals("y"))
{
data[amount] = int.Parse(input);
input = Console.ReadLine();
amount++;
}
int[,] total = new int[amount, 2];//用于存储整形信息

//统计数组中重复元素的个数
for (int i = 0; i < amount; i++)
{
if (data[i] != -1)
{
temp1 = data[i];
for (int j = 0; j < amount; j++)
{
if (temp1 == data[j])
{
temp2++;
data[j] = -1;
}

}
total[k, 0] = temp1;
total[k, 1] = temp2;
temp2 = 0;
k++;
}
}
//输出统计数据

Console.WriteLine("数据\t数据出现的次数");
Console.WriteLine("=====================");
for (int i = 0; i < k; i++)
{
if (total[i, 0] != 0)
Console.WriteLine("{0}\t{1}", total[i, 0], total[i, 1]);

}