返回已用编号、缺号分布字符串的处理示例.sql
2012-05-19 09:13
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--生成已用编号分布字符串的函数
CREATE FUNCTION f_GetStrSeries(@col1 varchar(10))
RETURNS varchar(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=-1
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END
+','+CAST(col2 as varchar)
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,2,'')
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END)
END
GO
--生成缺号分布字符串的函数
CREATE FUNCTION f_GetStrNSeries(@col1 varchar(10))
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=0
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re+','+CAST(@pid+1 as varchar)
+CASE
WHEN @pid+1=col2-1 THEN ''
ELSE CAST(1-col2 as varchar)
END
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,1,''))
END
GO
--调用测试
--测试数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',5
UNION ALL SELECT 'a',8
UNION ALL SELECT 'a',9
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7
--查询
SELECT col1,
col2_Series=dbo.f_GetStrSeries(col1),
col2_Series=dbo.f_GetStrNSeries(col1)
FROM tb
GROUP BY col1
/*--结果
col1 col2_Series col2_Series
-------------- ------------------------ --------------
a 2-3,5,8-9 1,4,6-7
b 1,5-7 2-4
--*/
CREATE FUNCTION f_GetStrSeries(@col1 varchar(10))
RETURNS varchar(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=-1
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END
+','+CAST(col2 as varchar)
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,2,'')
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END)
END
GO
--生成缺号分布字符串的函数
CREATE FUNCTION f_GetStrNSeries(@col1 varchar(10))
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=0
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re+','+CAST(@pid+1 as varchar)
+CASE
WHEN @pid+1=col2-1 THEN ''
ELSE CAST(1-col2 as varchar)
END
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,1,''))
END
GO
--调用测试
--测试数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',5
UNION ALL SELECT 'a',8
UNION ALL SELECT 'a',9
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7
--查询
SELECT col1,
col2_Series=dbo.f_GetStrSeries(col1),
col2_Series=dbo.f_GetStrNSeries(col1)
FROM tb
GROUP BY col1
/*--结果
col1 col2_Series col2_Series
-------------- ------------------------ --------------
a 2-3,5,8-9 1,4,6-7
b 1,5-7 2-4
--*/
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