使用C#操作Access参数形式的模糊查询方法

代码记录一下：

1public static DataTable getByName(string typeName)

2 {

3 StringBuilder sb = new StringBuilder();

4 sb.Append("select * from type1 where typeName like @typeName");

5 OleDbParameter[] param =

6 {

7 OleDbHelper.GetParameter("@typeName",OleDbType.VarChar,50,"[typeName]","%"+typeName+"%")

8 };

9 return OleDbHelper.ExecuteDt(sb.ToString(), param);

10 }