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特殊SQL示例

2012-02-28 16:01 218 查看
ProductsData

pd_num          pd_type  pd_status

SCS-1-00       SCS-1     0

SCS-1-002     SCS-1     0

SCS-2-001     SCS-2     0

SCS-2-001     SCS-2     1

结果(num1 是pd_status=0的个数,num1 是pd_status=1的个数)

pd_type num1   num2

scs-1     2           0
scs_2   1            1

select distinct t3.up_type, t3.up_num, iif(isnull(t4.num), 0, t4.num) as non_num from

(select distinct t1.pd_type as up_type, iif(ISNULL(t2.num), 0,t2.num) as up_num from ProductsData as t1
left join
(select pd_type, count(pd_num) as num from ProductsData where pd_status = 0 group by pd_type) as t2 on t1.pd_type = t2.pd_type) as t3
left join
(select pd_type, count(pd_num) as num from ProductsData where pd_status = 1 group by pd_type) as t4 on t4.pd_type = t3.up_type
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标签:  sql join up