您的位置:首页 > 编程语言 > Java开发

Spring MVC:使用SimpleUrlHandlerMapping的一个简单例子

2011-12-01 11:26 211 查看

实现一个控制器ShirdrnController,如下所示:

package org.shirdrn.spring.mvc;

import java.util.Date;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.Controller;

public class ShirdrnController implements Controller {

public ModelAndView handleRequest(HttpServletRequest arg0,
    HttpServletResponse arg1) throws Exception {
   Log logger = LogFactory.getLog(getClass());
   Date date = new Date();
   logger.info("信息 : ["+date.toLocaleString()+"]调用控制器ShirdrnController,转向index.jsp页面.");
   return new ModelAndView("index.jsp");
}
}

当给控制器接收到请求后,转发向index.jsp页面。

在目录/WEB-INF/下面创建一个Spring配置文件,格式为<SERVLET-NAME>-servlet.xml,例如 shirdrn-servlet.xml,其中shirdrn对应于web.xml中配置的<servlet-name>。在 shirdrn-servlet.xml中装配上面实现的控制器org.shirdrn.spring.mvc.ShirdrnController,配置如下所示:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">

<beans>
<bean id="shirdrnController"
   class="org.shirdrn.spring.mvc.ShirdrnController" abstract="false"
   singleton="true" lazy-init="default" autowire="default"
   dependency-check="default">
</bean>

<bean id="shirdrnUrlMapping"
   class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"
   abstract="false" singleton="true" lazy-init="default"
   autowire="default" dependency-check="default">
   <property name="mappings">
    <props>
    <prop key="/shirdrn.abc">shirdrnController</prop>
    </props>
   </property>
</bean>
</beans>

上面,如果请求为shirdrn.abc的时候,则调用shirdrnController控制器,将转向index.jsp页面,生成视图。

在web.xml中配置如下所示:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<servlet>
   <servlet-name>shirdrn</servlet-name>
   <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
   <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
   <servlet-name>shirdrn</servlet-name>
   <url-pattern>*.abc</url-pattern>
</servlet-mapping>

<welcome-file-list>
   <welcome-file>index.jsp</welcome-file>
</welcome-file-list>

</web-app>

就是,当请求的URL以.abc为后缀的时候,都交由Servlet名称为shirdrn的org.springframework.web.servlet.DispatcherServlet控制视图转发。

编写一个简单的JSP页面index.jsp,如下所示:

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
    <base href="<%=basePath%>">
   
    <title>第一个Spring MVC应用</title>
   
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">   
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->

</head>

<body>
    <h1>我的第一个Spring MVC应用</h1>
    <hr><hr>
    <hr><hr>
    <center>当前时间为 : <%=new java.util.Date() %></center>
</body>
</html>

启动Tomcat Web 服务器,在浏览器地址栏中键入地址:

http://localhost:8080/SpringMVC/shirdrn.abc

可以看到输出index.jsp页面的内容,如图所示:

阅读更多
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: 
相关文章推荐