sql语法和MongoDB语法的对应关系
2011-11-25 14:37
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SQL Statement | Mongo Query Language Statement |
CREATE TABLE USERS (a Number, b Number) | db.createCollection( "mycoll", {capped:true , size:100000}) |
INSERT INTO USERS VALUES(1,1) | db.users.insert({a:1,b:1}) |
SELECT a,b FROM users | db.users.find({}, {a:1,b:1}) |
SELECT * FROM users | db.users.find() |
SELECT * FROM users WHERE age=33 | db.users.find({age:33}) |
SELECT a,b FROM users WHERE age=33 | db.users.find({age:33}, {a:1,b:1}) |
SELECT * FROM users WHERE age=33 ORDER BY name | db.users.find({age:33}).sort({name:1}) |
SELECT * FROM users WHERE age>33 | db.users.find({'age':{$gt:33}})}) |
SELECT * FROM users WHERE age<33 | db.users.find({'age':{$lt:33}})}) |
SELECT * FROM users WHERE name LIKE "%Joe%" | db.users.find({name:/Joe/}) |
SELECT * FROM users WHERE name LIKE "Joe%" | db.users.find({name:/^Joe/}) |
SELECT * FROM users WHERE age>33 AND age<=40 | db.users.find({'age':{$gt:33,$lte:40}})}) |
SELECT * FROM users ORDER BY name DESC | db.users.find().sort({name:-1}) |
CREATE INDEX myindexname ON users(name) | db.users.ensureIndex({name:1}) |
CREATE INDEX myindexname ON users(name,ts DESC) | db.users.ensureIndex({name:1,ts:-1}) |
SELECT * FROM users WHERE a=1 and b='q' | db.users.find({a:1,b:'q'}) |
SELECT * FROM users LIMIT 10 SKIP 20 | db.users.find().limit(10).skip(20) |
SELECT * FROM users WHERE a=1 or b=2 | db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } ) |
SELECT * FROM users LIMIT 1 | db.users.findOne() |
EXPLAIN SELECT * FROM users WHERE z=3 | db.users.find({z:3}).explain() |
SELECT DISTINCT last_name FROM users | db.users.distinct('last_name') |
SELECT COUNT(*y) FROM users | db.users.count() |
SELECT COUNT(*y) FROM users where AGE > 30 | db.users.find({age: {'$gt': 30}}).count() |
SELECT COUNT(AGE) from users | db.users.find({age: {'$exists': true}}).count() |
UPDATE users SET a=1 WHERE b='q' | db.users.update({b:'q'}, {$set:{a:1}}, false, true) |
UPDATE users SET a=a+2 WHERE b='q' | db.users.update({b:'q'}, {$inc:{a:2}}, false, true) |
DELETE FROM users WHERE z="abc" | db.users.remove({z:'abc'}); |
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