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获取数据库表结构和表数据的小程序(VB.NET版本)

2011-11-02 14:52 525 查看
以前在项目实施过程中经常要到客户方去进行调查。由于客户的生产网络环境是封闭的,而且不能去查看真实的数据库,因此做了个小程序来采集数据库中指定表的数据和指定表的结构。代码如下:

'GetTableStuct 获取表的结构

Private Function GetDataTableSchame(ByVal strTableName As String) As DataSet

On Error GoTo theError

InitialConnectionString()

Dim dba As New SqlDataProvider.DataBaseAccess(con_SPEC_DB)

Dim dsTableSchame As New DataSet

Dim strSql As String

'Get Table Schame

strSql = "SELECT syscolumns.name as columnname,systypes.name as columntype,syscolumns.isnullable," & _

"syscolumns.length FROM syscolumns, systypes " & _

"WHERE(syscolumns.xusertype = systypes.xusertype) " & _

" AND syscolumns.id = object_id('" & strTableName & "') "

dsTableSchame = dba.FillDataset(strSql, CommandType.Text)

Return dsTableSchame

Exit Function

theError:

MessageBox.Show("获取表" & strTableName & "的结构失败!")

Return Nothing

Exit Function

End Function

'GetTableData 获取表的数据

Private Function GetTableData(ByVal strTableName As String) As DataSet

On Error GoTo theError

InitialConnectionString()

Dim dba As New SqlDataProvider.DataBaseAccess(con_SPEC_DB)

Dim dsTableData As New DataSet

Dim strSql As String

'Get Table Schame

strSql = "select * from " & strTableName

dsTableData = dba.FillDataset(strSql, CommandType.Text)

Return dsTableData

Exit Function

theError:

MessageBox.Show("获取表" & strTableName & "的数据失败!")

Return Nothing

Exit Function

End Function

'将表的结构写入到文件中

Private Function WriteTableStruct(ByVal strTableName As String, ByVal fs As FileStream, ByVal sw As StreamWriter, ByVal ds As DataSet) As Boolean

If ds Is Nothing Then

Else

sw.WriteLine(ds.Tables(0).Columns(0).ColumnName & "," & ds.Tables(0).Columns(1).ColumnName & "," & _

ds.Tables(0).Columns(2).ColumnName & "," & ds.Tables(0).Columns(3).ColumnName)

Dim i As Int16

For i = 0 To ds.Tables(0).Rows.Count - 1

sw.WriteLine(ds.Tables(0).Rows(i)(0).ToString() & "," & ds.Tables(0).Rows(i)(1).ToString() & "," & _

ds.Tables(0).Rows(i)(2).ToString() & "," & ds.Tables(0).Rows(i)(3).ToString())

Next

sw.WriteLine("--------------------------------------")

sw.WriteLine()

End If

End Function

'将表的数据写入到文件中

Private Function WriteTableData(ByVal strTableName As String, ByVal fs As FileStream, ByVal sw As StreamWriter, ByVal ds As DataSet) As Boolean

If ds Is Nothing Then

Else

Dim j As Int16

For j = 0 To ds.Tables(0).Columns.Count - 1

If j = ds.Tables(0).Columns.Count - 1 Then

sw.Write(ds.Tables(0).Columns(j).ColumnName)

sw.WriteLine()

Else

sw.Write(ds.Tables(0).Columns(j).ColumnName & ",")

End If

Next

Dim i As Int16

For i = 0 To ds.Tables(0).Rows.Count - 1

For j = 0 To ds.Tables(0).Columns.Count - 1

If j = ds.Tables(0).Columns.Count - 1 Then

sw.Write(ds.Tables(0).Rows(i)(j).ToString())

sw.WriteLine()

Else

sw.Write(ds.Tables(0).Rows(i)(j).ToString() & ",")

End If

Next

Next

sw.WriteLine("--------------------------------------")

sw.WriteLine()

End If

End Function

‘调用上面程序的Demo代码如下:

’获取表结构的代码

Private Sub btnGetTableStruct_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnGetTableStruct.Click

On Error GoTo theError

Dim strPath As String

strPath = System.Windows.Forms.Application.StartupPath

'Create New File

Dim strOutputFileName As String

strOutputFileName = "TableStruct-" + DateTime.Now.ToString("yyyyMMddhhmmss")

strOutputFileName = strPath & "\" & strOutputFileName

Dim fs As System.IO.FileStream = New System.IO.FileStream(strOutputFileName & ".csv", IO.FileMode.CreateNew, IO.FileAccess.Write)

Dim sw As System.IO.StreamWriter = New System.IO.StreamWriter(fs)

Dim ds As New DataSet

ds = Nothing

Dim strTableName As String

strTableName = "Test"

sw.WriteLine(strTableName & "表结构如下:")

ds = GetDataTableSchame(strTableName)

WriteTableStruct(strTableName, fs, sw, ds)

ds.Clear()

sw.Close()

fs.Close()

MessageBox.Show("生成表结构文件成功!")

Exit Sub

theError:

MessageBox.Show("生成表结构文件失败!")

sw.Close()

fs.Close()

Exit Sub

End Sub

'获取表数据的代码

Private Sub btnGetTableData_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnCancel.Click

On Error GoTo theError

Dim strPath As String

strPath = System.Windows.Forms.Application.StartupPath

'Create New File

Dim strOutputFileName As String

strOutputFileName = "TableData-" + DateTime.Now.ToString("yyyyMMddhhmmss")

strOutputFileName = strPath & "\" & strOutputFileName

Dim fs As System.IO.FileStream = New System.IO.FileStream(strOutputFileName & ".csv", IO.FileMode.CreateNew, IO.FileAccess.Write)

Dim sw As System.IO.StreamWriter = New System.IO.StreamWriter(fs)

Dim ds As New DataSet

ds = Nothing

Dim strTableName As String

strTableName = "Test"

sw.WriteLine(strTableName & "表数据如下:")

ds = GetTableData(strTableName)

WriteTableData(strTableName, fs, sw, ds)

ds.Clear()

sw.Close()

fs.Close()

MessageBox.Show("生成表数据文件成功!")

Exit Sub

theError:

MessageBox.Show("生成表数据文件失败!")

sw.Close()

fs.Close()

Exit Sub

End Sub
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