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Oracle CONNECT BY的用法

2011-09-14 17:26 387 查看
Oracle中可以通过START WITH . . . CONNECT BY . . .子句来实现SQL的层次查询.

自从Oracle 9i开始,可以通过 SYS_CONNECT_BY_PATH 函数实现将父节点到当前行内容以“path”或者层次元素列表的形式显示出来。

自从Oracle 10g 中,还有其他更多关于层次查询的新特性 。例如,有的时候用户更关心的是每个层次分支中等级最低的内容。

那么你就可以利用伪列函数CONNECT_BY_ISLEAF来判断当前行是不是叶子。如果是叶子就会在伪列中显示“1”,

如果不是叶子而是一个分支(例如当前内容是其他行的父亲)就显示“0”。

在Oracle 10g 之前的版本中,如果在你的树中出现了环状循环(如一个孩子节点引用一个父亲节点),

Oracle 就会报出一个错误提示:“ ORA-01436: CONNECT BY loop in user data”。如果不删掉对父亲的引用就无法执行查询操作。

而在 Oracle 10g 中,只要指定“NOCYCLE”就可以进行任意的查询操作。与这个关键字相关的还有一个伪列——CONNECT_BY_ISCYCLE

如果在当前行中引用了某个父亲节点的内容并在树中出现了循环,那么该行的伪列中就会显示“1”,否则就显示“0”。

The start with .. connect by clause can be used to select data that has a hierarchical relationship

(usually some sort of parent->child, boss->employee or thing->parts).

It is also being used when an sql execution plan is explained.

syntax:

select ... [start with initial-condition] connect by [nocycle] recurse-condition

level

With level it is possible to show the level in the hierarchical relation of all the data.

--oracle 9i

sys_connect_by_path

With sys_connect_by_path it is possible to show the entire path from the top level down to the 'actual' child.

--oracle 10g

connect_by_root

connect_by_root is a new operator that comes with Oracle 10g and enhances the ability to perform hierarchical queries.

connect_by_is_leaf

connect_by_isleaf is a new operator that comes with Oracle 10g and enhances the ability to perform hierarchical queries.

connect_by_iscycle

connect_by_is_cycle is a new operator that comes with Oracle 10g and enhances the ability to perform hierarchical queries.

下面举例说明:

[例1]

创建一个部门表,这个表有4个字段,分别对应部门ID,部门名称,上级部门ID ,本部门直属员工人数。

create table DEP

(

DEPID number(10) not null,

DEPNAME varchar2(32),

UPPERDEPID number(10),

NUMOFEMP number(10)

) ;

下面插入一些数据,结果如下:

hr@MYTEST2> select * from dep;

DEPID DEPNAME         UPPERDEPID   NUMOFEMP
---------- --------------- ---------- ----------
0 Dev Center                          2
1 DevA                     0          3
2 DevA Team1               1         10
3 DevA Team2               1          8
4 DevB                     0          2
5 DevB Team1               4         12
6 Test Center                         1
7 Test Team1               6          5
8 Test Team2               6          5

9 rows selected.

现在根据“CONNECT BY”来实现树状查询:

column depname format a15;
column rootdep format a15;
column path format a30;

select rpad(' ', 2*(level-1), '-') || depname "DEPNAME",
connect_by_root depname "ROOTDEP",
connect_by_isleaf "ISLEAF",
level,
sys_connect_by_path(depname, '/') "PATH"
from dep
start with upperdepid is null
connect by prior depid = upperdepid
/

结果如下:

DEPNAME         ROOTDEP             ISLEAF      LEVEL PATH
--------------- --------------- ---------- ---------- ---------------------------
Dev Center      Dev Center               0          1 /Dev Center
-DevA          Dev Center               0          2 /Dev Center/DevA
---DevA Team1  Dev Center               1          3 /Dev Center/DevA/DevA Team1
---DevA Team2  Dev Center               1          3 /Dev Center/DevA/DevA Team2
-DevB          Dev Center               0          2 /Dev Center/DevB
---DevB Team1  Dev Center               1          3 /Dev Center/DevB/DevB Team1
Test Center     Test Center              0          1 /Test Center
-Test Team1    Test Center              1          2 /Test Center/Test Team1
-Test Team2    Test Center              1          2 /Test Center/Test Team2


下面计算Dev Center和Test Center部门的总人数:

select ROOTDEPID, sum(numofemp) "TOTALEMP"
from (select connect_by_root depid "ROOTDEPID", numofemp from dep
start with upperdepid is null
connect by prior depid = upperdepid)
group by ROOTDEPID
/

结果如下:

ROOTDEPID   TOTALEMP
---------- ----------
6         11
0         37


[例2]

通过CONNECT BY用于十六进度转换为十进制

CREATE OR REPLACE FUNCTION f_hex_to_dec(p_str IN VARCHAR2) RETURN VARCHAR2 IS
----------------------------------------------------------------------------------------------------------------------
-- 对象名称: f_hex_to_dec
-- 对象描述: 十六进制转换十进制
-- 输入参数: p_str 十六进制字符串
-- 返回结果: 十进制字符串
-- 测试用例: SELECT f_hex_to_dec('78A') FROM dual;
----------------------------------------------------------------------------------------------------------------------
v_return  VARCHAR2(4000);
BEGIN
SELECT SUM(DATA) INTO v_return
FROM (SELECT (CASE upper(substr(p_str, rownum, 1))
WHEN 'A' THEN '10'
WHEN 'B' THEN '11'
WHEN 'C' THEN '12'
WHEN 'D' THEN '13'
WHEN 'E' THEN '14'
WHEN 'F' THEN '15'
ELSE substr(p_str, rownum, 1)
END) * power(16, length(p_str) - rownum) DATA
FROM dual
CONNECT BY rownum <= length(p_str));
RETURN v_return;
EXCEPTION
WHEN OTHERS THEN
RETURN NULL;
END;


说明:

1. CONNECT BY rownum <= length(p_str))对输入的字符串进行逐个遍历

2. 通过CASE语句,来解析十六进制中的A-F对应的10进制值

测试结果如下:

hr@MYTEST2> variable dec varchar2(32);
hr@MYTEST2> exec :dec := f_hex_to_dec('1FF');

PL/SQL procedure successfully completed.

hr@MYTEST2> print dec

DEC
----------
511


[例3]

通过CONNECT BY生成序列

对于connect by,现在大多数人已经很熟悉了,connect by中的条件就表示了父子之间的连接关系,比如 connect by id=prior pid。

但如果connect by中的条件没有表示记录之间的父子关系

那会出现什么情况?

常见的,connect by会在构造序列的时候使用

用select rownum from dual connect by rownum<xxx 代替早期版本的 select rownum from all_objects where rownum <xxx

我们注意到,dual是一个只有一条记录的表,如果表有多条记录,将会怎样?

下面开始实验

CREATE TABLE T(ID VARCHAR2(1 BYTE));

INSERT INTO T ( ID ) VALUES ( 'A');

INSERT INTO T ( ID ) VALUES ( 'B');

INSERT INTO T ( ID ) VALUES ( 'C');

COMMIT;

然后执行以下查询:

hr@MYTEST2> column id format a2;
hr@MYTEST2> select id,level from t connect by level<2;

ID      LEVEL
-- ----------
A           1
B           1
C           1

hr@MYTEST2> select id,level from t connect by level<3;

ID      LEVEL
-- ----------
A           1
A           2
B           2
C           2
B           1
A           2
B           2
C           2
C           1
A           2
B           2
C           2

12 rows selected.


无需多说,我们很快可以找到其中的规律,假设表中有N条记录

则记F(N,l)为 select id,level from t connect by level<l 的结果集数目

那么,

F(N,1)=N

F(N,l) = F(N,l-1)*N+N

于是可以总结出

F(N,l)=∑power(N,p), p取值为[1,l)

要解释,也很容易。

当连接条件不能限制记录之间的关系时

每一条记录都可以作为自己或者其他记录的叶子

如下所示:

A 1

A 2

A 3

B 3

C 3

B 2

A 3

B 3

C 3

C 2

A 3

B 3

C 3

在这里,我们看到的是

Oracle采用了深度优先的算法

转载自:

http://www.blogjava.net/wxqxs/archive/2008/08/15/222338.html

http://www.cnblogs.com/lettoo/archive/2010/08/03/1791239.html

http://www.itpub.net/thread-994465-1-1.html
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