javax.management.MalformedObjectNameException: Invalid character '' in value part of property ，Oracle 驱动包的错误
2011-06-14 10:17
881 查看
在项目的spring 中使用了 Oracle的jdbd，驱动包是 ojdbc6.jar.
发现错误：
javax.management.MalformedObjectNameException: Invalid character '' in value part of property
发现还是jdbc驱动问题，原因因该是与bug有关，因此从新从otn.oracle.com下载驱动升级解决问题。
ojdbc6.jar的驱动版本可以运行java -jar ojdbc6.jar查看，如果是Oracle 11.1.0.6.0-Production+ JDBC 4.0 compiled with JDK6，带+号就是补丁版本，否则是没有打补丁的，仍然可能出错。
或者直接下载 Oracle 11.1.0.7.0-Production JDBC 4.0 compiled with JDK6 这个包的ojdbc6.jar
下载地址
http://www.oracle.com/technology/tech/java/sqlj_jdbc/index.html
发现错误：
javax.management.MalformedObjectNameException: Invalid character '' in value part of property
发现还是jdbc驱动问题，原因因该是与bug有关，因此从新从otn.oracle.com下载驱动升级解决问题。
ojdbc6.jar的驱动版本可以运行java -jar ojdbc6.jar查看，如果是Oracle 11.1.0.6.0-Production+ JDBC 4.0 compiled with JDK6，带+号就是补丁版本，否则是没有打补丁的，仍然可能出错。
或者直接下载 Oracle 11.1.0.7.0-Production JDBC 4.0 compiled with JDK6 这个包的ojdbc6.jar
下载地址
http://www.oracle.com/technology/tech/java/sqlj_jdbc/index.html
内容来自用户分享和网络整理，不保证内容的准确性，如有侵权内容，可联系管理员处理 
相关文章推荐
- javax.management.MalformedObjectNameException: Invalid character '' in value part of property ，Oracle 驱动包的错误
- avax.management.MalformedObjectNameException: Invalid character '' in value part of property ，Oracle
- BUG之javax.management.MalformedObjectNameException: Invalid character '=' in value part of property
- javax.management.MalformedObjectNameException: Invalid character '\n' in value part of property
- tomcat,javax.management.MalformedObjectNameException: Invalid character ':' in value part of propert
- javax.management.MalformedObjectNameException: Invalid character '' in value par
- MalformedObjectNameException: Invalid character '' in value part of property
- Oracle Invalid character ' ' in value part of property error
- websphere7下报错：javax.management.MalformedObjectNameException: Invalid character 的解决办法
- JAVA错误：Error while registering Oracle JDBC Diagnosability MBean. javax.management.MalformedObjectNameException:
- 解决编译错误：Property 'value' not found on object of type '_strong id'
- Caused by: org.springframework.beans.NullValueInNestedPathException: Invalid property 'xxxx'
- Android javax.net.ssl.SSLException: hostname in certificate didn't match...
- UIView CALayer 属性不显示错误 Property cannot be found in forward class object 'CALayer
- javax.servlet.ServletException: javax.servlet.jsp.JspTagException: Invalid property in <set>: "age2"
- tomcat 启动异常javax.management.MalformedObjectNameException: Invalid character ':' in value part of property
- Cannot convert value of type [java.lang.String] to required type [javax.sql.DataSource] for property 'dataSource': no matching e
- Error occurred in deployment step 'Retract Solution': Invalid object name 'AllWebs'
- freemarker.core.InvalidReferenceException: Expression stackObject.value.get(propertyName).toString() is undefined
- javax.net.ssl.SSLException: hostname in certificate didn't match: