一道关于员工与部门查询的SQL笔试题

01

DEPARTMENTS:

02

DEPARTMENT_ID(primary key),

03

DEPARTMENT_NAME,

04

LOCATION

05

06

EMPLOYEES:

07

EMPLOYEE_ID(primary key),

08

EMPLOYEE_NAME,

09

EMPLOYEE_JOB,

10

MANAGER,

11

SALARY,

12

DEPARTMENT_ID

1

selectmax(SALARY)

as

最高工资,min(SALARY)

as

最低工资,DEPARTMENT_IDfrom EMPLOYEES group by DEPARTMENT_ID;

1

selectmax(SALARY)

as

最高工资,min(SALARY)

as

最低工资,DEPARTMENT_ID

as

部门号 from EMPLOYEESwhere EMPLOYEE_JOB =

'CLERK'

group by DEPARTMENT_ID;

1

selectmax(SALARY)

as

最高工资,min(SALARY)

as

最低工资,DEPARTMENT_ID

as

部门号 from EMPLOYEES

as

b

2

where EMPLOYEE_JOB =

'CLERK'

and

1000>(selectmin(SALARY) from EMPLOYEES

as

a where a.DEPARTMENT_ID = b.DEPARTMENT_ID) group by b.DEPARTMENT_ID

1

selectDEPARTMENT_ID

as

部门号,EMPLOYEE_NAME

as

姓名,SALARY

as

工资 from EMPLOYEESorder by DEPARTMENT_ID desc,SALARY asc

1

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1

selectEMPLOYEE_NAME,DEPARTMENT_ID from EMPLOYEES where DEPARTMENT_ID = (selectDEPARTMENT_IDfrom EMPLOYEES where EMPLOYEE_NAME = 

'张三'

)

1

selectEMPLOYEE_NAME,EMPLOYEE_JOB,EMPLOYEES.DEPARTMENT_ID,DEPARTMENTS.DEPARTMENT_NAME from EMPLOYEES,DEPARTMENTS where EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID

1

selectEMPLOYEE_NAME,EMPLOYEE_JOB,DEPARTMENTS.DEPARTMENT_ID,DEPARTMENT_NAME from EMPLOYEES,DEPARTMENTS where DEPARTMENTS.DEPARTMENT_ID = EMPLOYEES.DEPARTMENT_ID

and

DEPARTMENT_JOB =

'CLERK'

1

selecta.EMPLOYEE_NAME

as

姓名,b.EMPLOYEE_NAME

as

管理者 from EMPLOYEES

as

a,EMPLOYEES

as

b where a.MANAGER is not null

and

a.MANAGER = b.EMPLOYEE_ID

1

selectDEPARTMENT_NAME

as

部门名,DEPARTMENTS.DEPARTMENT_ID

as

部门号,EMPLOYEE_NAME

as

员工名,EMPLOYEE_JOB

as

工作 from DEPARTMENTS,EMPLOYEES

2

where DEPARTMENTS.DEPARTMENT_ID *= EMPLOYEES.DEPARTMENT_ID

and

EMPLOYEE_JOB =

'CLERK'

1

selecta.DEPARTMENT_ID

as

部门号,a.EMPLOYEE_NAME

as

姓名,a.SALARY

as

工资 from EMPLOYEES

as

a

2

where a.SALARY>(selectavg(SALARY) from EMPLOYEES

as

b where a.DEPARTMENT_ID = b.DEPARTMENT_ID) order by a.DEPARTMENT_ID

1

select

count

(a.SALARY)

as

员工数,a.DEPARTMENT_ID

as

部门号 from EMPLOYEES

as

a

2

where a.SALARY>(selectavg(SALARY) from EMPLOYEES

as

b where a.DEPARTMENT_ID = b.DEPARTMENT_ID) group by a.DEPARTMENT_ID order by a.DEPARTMENT_ID

1

select

count

(a.EMPLOYEE_ID)

as

员工数,a.DEPARTMENT_ID

as

部门号,avg(SALARY)

as

平均工资 from EMPLOYEES

as

a

2

where (select

count

(c.EMPLOYEE_ID) from EMPLOYEES

as

c where c.DEPARTMENT_ID = a.DEPARTMENT_ID

and

c.SALARY>(selectavg(SALARY) from EMPLOYEES 

as

b where c.DEPARTMENT_ID = b.DEPARTMENT_ID))>1

3

group by a.DEPARTMENT_ID order by a.DEPARTMENT_ID

1

selecta.DEPARTMENT_ID,a.EMPLOYEE_NAME,a.SALARY,(select

count

(b.EMPLOYEE_NAME) from EMPLOYEES

as

b where b.SALARY < a.SALARY)

as

人数 from EMPLOYEES

as

a

2

where (select

count

(b.EMPLOYEE_NAME) from EMPLOYEES

as

b where b.SALARY<a.SALARY)>5