SQL语句练习题

练习题目

1、 查询Student表中的所有记录的Sname、Ssex和Class列。
2、 查询教师所有的单位即不重复的Depart列。
3、 查询Student表的所有记录。
4、 查询Score表中成绩在60到80之间的所有记录。
5、 查询Score表中成绩为85，86或88的记录。
6、 查询Student表中“95031”班或性别为“女”的同学记录。
7、 以Class降序查询Student表的所有记录。
8、 以Cno升序、Degree降序查询Score表的所有记录。
9、 查询“95031”班的学生人数。
10、查询Score表中的最高分的学生学号和课程号。
11、查询‘3-105’号课程的平均分。
12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。
13、查询最低分大于70，最高分小于90的Sno列。
14、查询所有学生的Sname、Cno和Degree列。
15、查询所有学生的Sno、Cname和Degree列。
16、查询所有学生的Sname、Cname和Degree列。
17、查询“95033”班所选课程的平均分。
18、假设使用如下命令建立了一个grade表：

19、查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。
20、查询score中选学一门以上课程的同学中分数为非最高分成绩的记录。
21、查询成绩高于学号为“109”、课程号为“3-105”的成绩的所有记录。
22、查询和学号为108的同学同年出生的所有学生的Sno、Sname和Sbirthday列。
23、查询“张旭“教师任课的学生成绩。
24、查询选修某课程的同学人数多于5人的教师姓名。
25、查询95033班和95031班全体学生的记录。
26、查询存在有85分以上成绩的课程Cno.
27、查询出“计算机系“教师所教课程的成绩表。
28、查询“计算机系”与“电子工程系“不同职称的教师的Tname和Prof。
29、查询选修编号为“3-105“课程且成绩至少高于选修编号为“3-245”的同学的Cno、Sno和Degree,并按Degree从高到低次序排序。
30、查询选修编号为“3-105”且成绩高于选修编号为“3-245”课程的同学的Cno、Sno和Degree.
31、查询所有教师和同学的name、sex和birthday.
32、查询所有“女”教师和“女”同学的name、sex和birthday.
33、查询成绩比该课程平均成绩低的同学的成绩表。
34、查询所有任课教师的Tname和Depart.
35 查询所有未讲课的教师的Tname和Depart.
36、查询至少有2名男生的班号。
37、查询Student表中不姓“王”的同学记录。
38、查询Student表中每个学生的姓名和年龄。
39、查询Student表中最大和最小的Sbirthday日期值。
40、以班号和年龄从大到小的顺序查询Student表中的全部记录。
41、查询“男”教师及其所上的课程。
42、查询最高分同学的Sno、Cno和Degree列。
43、查询和“李军”同性别的所有同学的Sname.
44、查询和“李军”同性别并同班的同学Sname.
45、查询所有选修“计算机导论”课程的“男”同学的成绩表

SQL语句练习题参考答案
1、 select Sname,Ssex,Class from Student;
2、 select distinct depart from teacher;
3、 select Sno as '学号',Sname as '姓名',Ssex as '性别',Sbirthday as'出生日期',Class as'班号'from student;
或
select Sno as 学号,Sname as 姓名,Ssex as 性别,Sbirthday as 出生日期,Class as 班号 from student;
4、 select * from score where degree between 60 and 80;
或select * from score where degree>=60 and degree<=80;
5、 select * from score where degree in (85,86,88);
6、 select * from student where class='95031'or Ssex='女';
7、 select * from student order by class desc;
8、 select * from score order by cno asc ,degree desc;
或select * from score order by cno ,degree desc;
9、 select count(*) as CNT from student where class='95031';
10、select Sno as '学号',cno as '课程号', degree as '最高分' from score
where degree=(select max(degree) from score)
11、select avg(degree)as 课程平均分 from score where cno='3-105';
12、select cno,avg(degree) from score where cno like'3%'group by cno having count(*) >5;
13、select Sno from score group by Sno having min(degree)>70 and max(degree)<90;
14、select student.Sname,score.Cno,score.degree from student,score where student.Sno=score.Sno;
15、select x.Sno,y.Cname,x.degree from score x,course y where x.Cno=y.Cno;
16、select x.Sname,y.Cname,z.degree from student x,course y,score z where x.Sno=z.Sno and z.Cno=y.Cno;
17、select y.Cno,avg(y.degree) from student x,score y where x.Sno=y.Sno and x.class='95033'group by y.cno;
18、select Sno,Cno,rank from score,grade where degree between low and upp order by rank;
19、select x.Cno,x.Sno,x.degree from score x,score y
where x.cno='3-105' and x.degree>y.degree and y.sno='109'and y.cno='3-105';
20、
1,查询成绩非本科最高 select * from score b where degree <(select max(degree) from score a where a.cno=b.cno);
2,查询成绩非本科最高并且选2门以上的学生的成绩:
21、select x.cno,x.Sno,x.degree from score x,score y where x.degree>y.degree and y.sno='109'and y.cno='3-105';
select cno,sno,degree from score where degree >(select degree from score where sno='109' and cno='3-105')
22、select sno,sname,sbirthday from student where to_char(sbirthday,'yyyy')=(select to_char(sbirthday,'yyyy') from student where sno='108');
23、select cno,sno,degree from score where cno=(select x.cno from course x,teacher y where x.tno=y.tno and y.tname='张旭');
24、select tname from teacher where tno in(select x.tno from course x,score y where x.cno=y.cno group by x.tno having count(x.tno)>5);
25、select * from student where class in('95033','95031');
26、select distinct cno from score where degree in (select degree from score where degree>85);
27、select * from score where cno in(select x.cno from course x,teacher y where y.tno=x.tno and y.depart='计算机系');
28、select tname,prof from teacher where depart='计算机系' and prof not in (select prof from teacher where depart='电子工程系');
29、select * from score where cno='3-105' and degree>any (select degree from score where cno='3-245')order by degree desc;
30、select * from score where cno='3-105' and degree>all(select degree from score where cno='3-245');
31、select tname,tsex,tbirthday from teacher
union select sname,ssex,sbirthday from student;
32、select tname,tsex,tbirthday from teacher where tsex='女'
union select sname,ssex,sbirthday from student where ssex='女';
33、select * from score a where degree<(select avg(degree)
from score b where a.cno=b.cno);
34、select tname,depart from teacher a where exists
(select * from course b where a.tno=b.tno);
35、select tname,depart from teacher a where not exists
(select * from course b where a.tno=b.tno);
36、select class from student where ssex='男'group by class having count(*)>=2;
37、select * from student where sname not like'王_';
38、select sname as 姓名,(to_char(sysdate,'yyyy')-to_char(sbirthday,'yyyy')) as 年龄 from student
39、select sname,sbirthday as 最大 from student where sbirthday =(select min (sbirthday) from student)
union select sname,sbirthday as 最小 from student where sbirthday =(select max(sbirthday) from student)
40、select class,sname,sbirthday from student order by class desc,sbirthday;
41、select x.tname,y.cname from teacher x,course y where x.tno=y.tno and x.tsex='男';
42、select * from score where degree=(select max(degree)from score);
43、select sname from student where ssex=(select ssex from student where sname='李军');
44、select sname from student where ssex=(select ssex from student where sname='李军') and class=(select class from student where sname='李军');
45、select * from score where sno in(select sno from student where ssex='男') and cno=(select cno from course
where cname='计算机导论');