查找某个字段最大值的记录 SQL 语句

查找某个字段最大值的记录 MS SQL

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某个字段查找最大值的记录.

　　select table_name.* from table_name,(select max(price) as price,pid from table_name group by pid) as table_name_temp where table_name_temp.price=table_name.price and table_name_temp.pid=table_name.pid;

--SQL code

create table lk1 (

uid int,

pid int,

price int,

`time` date

)engine=myisam;

insert into lk1 values

(1, 1, 100, '2007-07-01'),

(1, 2, 150, '2007-07-02 '),

(2, 1, 110, '2007-07-03 '),

(3, 1, 120, '2007-07-04 '),

(4, 2, 180, '2007-07-04 '),

(3, 2, 170, '2007-07-04 '),

(6, 3, 130, '2007-07-04 ');

select * from lk1 where price in (select max(price) from lk1 group by pid) group by pid;

--结果1：

query result(3 records)

uid pid price time

3 1 120 2007-07-04

4 2 180 2007-07-04

6 3 130 2007-07-04

truncate table lk1;

insert into lk1 values

(1, 1, 200, '2007-07-01'),

(1, 2, 200, '2007-07-02 '),

(2, 1, 110, '2007-07-03 '),

(3, 1, 120, '2007-07-04 '),

(4, 2, 180, '2007-07-04 '),

(3, 2, 170, '2007-07-04 '),

(6, 3, 130, '2007-07-04 ');

select * from lk1 where price in (select max(price) from lk1 group by pid) group by pid;

--结果2：

query result(3 records)

uid pid price time

1 1 200 2007-07-01

1 2 200 2007-07-02

6 3 130 2007-07-04

根据mysql的手册上面找到一个查询,修改了一下发现也可以实现,但是并不理解什么意思,不知道有没有人给解释一下

SQL codeSELECT *

FROM lk1 l1

WHERE price = (

SELECT MAX( l2.price )

FROM lk1 l2

WHERE l1.`pid` = l2.`pid` ) ;

--SQL code

create table lk1 (

uid int,

pid int,

price int,

`time` date

)engine=myisam;

insert into lk1 values

(1, 1, 100, '2007-07-01'),

(1, 2, 150, '2007-07-02 '),

(2, 1, 110, '2007-07-03 '),

(3, 1, 120, '2007-07-04 '),

(4, 2, 180, '2007-07-04 '),

(3, 2, 170, '2007-07-04 '),

(6, 3, 130, '2007-07-04 ');

select * from (select * from lk1 order by price desc) T group by pid;

--结果1：

query result(3 records)

uid pid price time

3 1 120 2007-07-04

4 2 180 2007-07-04

6 3 130 2007-07-04

truncate table lk1;

insert into lk1 values

(1, 1, 200, '2007-07-01'),

(1, 2, 200, '2007-07-02 '),

(2, 1, 110, '2007-07-03 '),

(3, 1, 120, '2007-07-04 '),

(4, 2, 180, '2007-07-04 '),

(3, 2, 170, '2007-07-04 '),

(6, 3, 130, '2007-07-04 ');

select * from (select * from lk1 order by price desc) T group by pid;

--结果2：

query result(3 records)

uid pid price time

1 1 200 2007-07-01

1 2 200 2007-07-02

6 3 130 2007-07-04

insert into lk1 values

(4, 3, 200, '2007-07-05 '),

(5, 3, 210, '2007-07-05' );

select * from (select * from lk1 order by price desc) T group by pid;

--结果3：

query result(3 records)

uid pid price time

1 1 200 2007-07-01

1 2 200 2007-07-02

5 3 210 2007-07-05 阅读全文

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