计算机网络基础知识

#!/usr/bin/env python

# Created on 2012-7-5 by Eric
# About calculate the days between the two dates

def isComYear(year):# judge if a certain year is a common year in which February only has 28 days
if year%100 == 0:
if (year/100)%4 == 0:
return 0
else:
return 1
else:
if year%4 == 0:
return 0
else:
return 1

def daysInMonth(year,month):#calculate the total days in a certain month in a certain year
bigMonth = [1, 3, 5, 7, 8, 10, 12]
if month in bigMonth:
return 31
elif month == 2:
if isComYear(year):
return 28
else:
return 29
else:
return 30

def daysInYear(year):#calculate the total days in a certain year
if isComYear(year):
return 365
else:
return 366

def distance(date1,date2): # first sort the two date
list1 = []
list2 = []
result = 0
for ele in date1.split("/"):
list1.append(int(ele))
for ele in date2.split("/"):
list2.append(int(ele))
print list1
print list2
list1,list2 = min(list1,list2),max(list1,list2)

if list1[0] == list2[0]: # equal year
if list1[1] == list2[1]: # equal month
result = list1[2] - list2[2]
else:
result1 = 0
for month in range(list1[1],list2[1]):
result1 += daysInMonth(list1[0],month)
result = result1 - list1[2] + list2[2]
else:
#if year is not equal,we won't care if the month is equal.We will only
#care the first year's remaining days,the last year's passed days and the total days between the two years
result2 = 0
result3 = 0
result4 = 0
for year in range(list1[0],list2[0]):
result2 += daysInYear(year)
if list1[1] == 1:
result3 = list1[2] - 1
else:
for month in range(1,list1[1]):
result3 += daysInMonth(list1[0],month)
if list2[1] == 1:
result4 = list[2]
else:
for month in range(1,list2[1]):
result4 += daysInMonth(list2[0],month)
result = result2 - result3 + result4
return result

def main():
date1 = raw_input("input the first date in the format YY/MM/DD : ")
date2 = raw_input("input the second date in the format YY/MM/DD: ")
dist = distance(date1,date2)
print "the distance between the two date is:",abs(dist)

if __name__ == '__main__':
main()