C#函数传参的out与ref的应用(转)
2010-06-10 15:22
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下面我总结下我对out和ref引用参数的看法:
1.out和ref引用参数的相同点:都是通过引用传递参数给函数;
2.out和ref引用参数的不同点是:用ref引用传递参数,该参数必须经过初始化,并且不能在调用它的函数中初始化,以下例子是错误的:
namespace refConsoleApp
{
class MyRefClass
{
static void MyRefMethod(ref int i)
{
int i=20;
}
static void main(string[] args)
{
int value; //not initialized the value;
MyRefMethod(ref value);
Console.WriteLine("The value is {0}",value);
}
}
}
3.使用out引用多个参数来返回多个值,这允许方法任意地返回需要的值,以下例子:
namespace multi_outConsoleApp
{
class MyMultipleoutClass
{
static void MyMultipleMethod(out int i, out string str1, out string str2)
{
i = 20;
str1 = "I was born";
str2 = "zhaoqing";
}
static void Main(string[] args)
{
int value;
string s1, s2;
MyMultipleMethod(out value,out s1,out s2);
Console.WriteLine("The integer value is {0} The first string value is {1} The second string value is {2}", value, s1, s2);
}
}
}
显示的结果为:
The integer value is 20
The first string value is I was born
The second string value is zhaoqing
4. 如果一个方法使用ref引用参数,另一个方法使用out引用参数,则这两个相同方法名的函数不能重载,否则出现编译错误,以下例子出现: " cannot define overloaded methods that differ only on ref and out "
namespace overloadofConsoleApp
{
class overloadofclass
{
static void MyMethod(ref int i)
{
i = 20;
}
static void MyMethod(out int i)
{
i = 40;
}
static void Main(string[] args)
{
int refvalue=0;
MyMethod(ref refvalue);
Console.WriteLine("The value is {0}", refvalue);
int outvalue;
MyMethod(out outvalue);
Console.WriteLine("The value is {0}", outvalue);
}
}
}
以下例子是正确的:
namespace overloadofConsoleApp
{
class overloadofclass
{
static void MyMethod(ref int i)
{
i = 20;
}
static void MyMethod( int i)
{
i = 40;
}
static void Main(string[] args)
{
int refvalue=0;
MyMethod(ref refvalue);
Console.WriteLine("The value is {0}", refvalue);
int outvalue=0;
MyMethod(outvalue);
Console.WriteLine("The value is {0}", outvalue);
}
}
}
显示结果为:
The value is 20
The value is 0
5.通过ref参数来改变引用类型,因为引用类型作为ref参数来传递,同时该对象会被改变.以下例子:
namespace refConsoleApp
{
class refclass
{
static void RefMethod(ref string s)
{
s = "I was born in zhaoqing";
}
static void Main(string[] args)
{
string str = "I am goalbell";
RefMethod(ref str);
Console.WriteLine("The value is {0}", str);
}
}
}
显示结果:
The value is I was born in zhaoqing
6.通过ref和out来传递数组,用ref传递数组的时候,必须在main函数里面初始化一个数组,而在被调用的方法中可以指定一个数组为空值或者初始 化成一个不同的数组;用out 传递数组的时候,在被调用的方法中确定为一个数组赋值.以下例子来区别一下它们:
namespace refszConsoleApp
{
class refszclass
{
static void RefszMethod(ref int[] arr)
{
if (arr == null) //assigned the null value
{
arr = new int[5]; //initialized to a different array
}
}
static void Main(string[] args)
{
int[] theArray ={ 1, 2, 3, 4, 5 };//initialize the theArray
RefszMethod(ref theArray); // pass the value using of ref
Console.WriteLine("Array elements are:");
for (int i = 0; i < theArray.Length; i++)
{
Console.WriteLine(theArray[i] + "");
}
}
}
}
namespace outszConsoleApp
{
class outszclass
{
static void OutszMethod(out int[] arr)
{
arr = new int[5] { 1, 2, 3, 4, 5 };//initialize the arr
}
static void Main(string[] args)
{
int[] theArray ;
OutszMethod(out theArray);
Console.WriteLine("Array elements are:");
for (int i = 0; i < theArray.Length; i++)
{
Console.WriteLine(theArray[i] + "");
}
}
}
}
1.out和ref引用参数的相同点:都是通过引用传递参数给函数;
2.out和ref引用参数的不同点是:用ref引用传递参数,该参数必须经过初始化,并且不能在调用它的函数中初始化,以下例子是错误的:
namespace refConsoleApp
{
class MyRefClass
{
static void MyRefMethod(ref int i)
{
int i=20;
}
static void main(string[] args)
{
int value; //not initialized the value;
MyRefMethod(ref value);
Console.WriteLine("The value is {0}",value);
}
}
}
3.使用out引用多个参数来返回多个值,这允许方法任意地返回需要的值,以下例子:
namespace multi_outConsoleApp
{
class MyMultipleoutClass
{
static void MyMultipleMethod(out int i, out string str1, out string str2)
{
i = 20;
str1 = "I was born";
str2 = "zhaoqing";
}
static void Main(string[] args)
{
int value;
string s1, s2;
MyMultipleMethod(out value,out s1,out s2);
Console.WriteLine("The integer value is {0} The first string value is {1} The second string value is {2}", value, s1, s2);
}
}
}
显示的结果为:
The integer value is 20
The first string value is I was born
The second string value is zhaoqing
4. 如果一个方法使用ref引用参数,另一个方法使用out引用参数,则这两个相同方法名的函数不能重载,否则出现编译错误,以下例子出现: " cannot define overloaded methods that differ only on ref and out "
namespace overloadofConsoleApp
{
class overloadofclass
{
static void MyMethod(ref int i)
{
i = 20;
}
static void MyMethod(out int i)
{
i = 40;
}
static void Main(string[] args)
{
int refvalue=0;
MyMethod(ref refvalue);
Console.WriteLine("The value is {0}", refvalue);
int outvalue;
MyMethod(out outvalue);
Console.WriteLine("The value is {0}", outvalue);
}
}
}
以下例子是正确的:
namespace overloadofConsoleApp
{
class overloadofclass
{
static void MyMethod(ref int i)
{
i = 20;
}
static void MyMethod( int i)
{
i = 40;
}
static void Main(string[] args)
{
int refvalue=0;
MyMethod(ref refvalue);
Console.WriteLine("The value is {0}", refvalue);
int outvalue=0;
MyMethod(outvalue);
Console.WriteLine("The value is {0}", outvalue);
}
}
}
显示结果为:
The value is 20
The value is 0
5.通过ref参数来改变引用类型,因为引用类型作为ref参数来传递,同时该对象会被改变.以下例子:
namespace refConsoleApp
{
class refclass
{
static void RefMethod(ref string s)
{
s = "I was born in zhaoqing";
}
static void Main(string[] args)
{
string str = "I am goalbell";
RefMethod(ref str);
Console.WriteLine("The value is {0}", str);
}
}
}
显示结果:
The value is I was born in zhaoqing
6.通过ref和out来传递数组,用ref传递数组的时候,必须在main函数里面初始化一个数组,而在被调用的方法中可以指定一个数组为空值或者初始 化成一个不同的数组;用out 传递数组的时候,在被调用的方法中确定为一个数组赋值.以下例子来区别一下它们:
namespace refszConsoleApp
{
class refszclass
{
static void RefszMethod(ref int[] arr)
{
if (arr == null) //assigned the null value
{
arr = new int[5]; //initialized to a different array
}
}
static void Main(string[] args)
{
int[] theArray ={ 1, 2, 3, 4, 5 };//initialize the theArray
RefszMethod(ref theArray); // pass the value using of ref
Console.WriteLine("Array elements are:");
for (int i = 0; i < theArray.Length; i++)
{
Console.WriteLine(theArray[i] + "");
}
}
}
}
namespace outszConsoleApp
{
class outszclass
{
static void OutszMethod(out int[] arr)
{
arr = new int[5] { 1, 2, 3, 4, 5 };//initialize the arr
}
static void Main(string[] args)
{
int[] theArray ;
OutszMethod(out theArray);
Console.WriteLine("Array elements are:");
for (int i = 0; i < theArray.Length; i++)
{
Console.WriteLine(theArray[i] + "");
}
}
}
}
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