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[Memo] Tips and Tricks for using C++ I/O.

2009-12-02 19:13 656 查看
From: http://www.augustcouncil.com/~tgibson/tutorial/iotips.html#prepare

There are three header files to include when using C++ I/OBy default, leading whitespace (carriage returns, tabs, spaces) is ignored by
cin
.
std::cin.getline()
can run into problems when used with
std::cin >> var
.Reading in numbers directly is problematicUsing getline to input numbers is a more robust alternate to reading numbers directlyOnce a file is opened, it may be used exactly as std::cin is used.When reading an entire file, embed the file input inside of the loop conditionGetline can be told to stop grabbing input at any designated characterDelimited files can easily be read using a while loop and getline. Using C++-style stringsHow to prepare the output stream to print fixed precision numbers (3.40 instead of 3.4)How to set the width of a printing fieldReturn to tutorial index

#include<iostream>
Include this file whenever using C++ I/O
#include<iomanip>
This file must be included for most C++ manipulators. If you don't know what a manipulator is, don't worry. Just include this file along with
iostream
and you can't go wrong
#include<fstream>
Include this file whenever working with files.
Given:

int i;
float fl;
std::cin >> fl;
std::cin >> i;

And you type:
3.14<return>42<return>

3.14 is read into
fl
. The carriage return (newline) following the 3.14 is still sitting on the input buffer.

Since std::cin ignores whitespace, the first return is "eaten" by
std::cin >> i
. Then the integer
42
is read into
i
and the second return is left on the input buffer.

getline
can be provided a third argument--a "stop" character. This character ends getline's input. The character is eaten and the string is terminated. Example:
std::cin.getline(str, 100, '|')


If
std::cin.getline()
is not provided a "stop" character as a third argument, it will stop when it reaches a newline.

Given:

float fl;
std::cin >> fl;
char str[101]
std::cin.getline(str, 101);


And you type:
3.14<return>


3.14 is read into
fl
. The newline following the 3.14 is still sitting on the input buffer.

std::cin.getline(str, 101)
immediately processes the newline that is still on the input buffer.
str
becomes an empty string.

The illusion is that the application "skipped" the
std::cin.getline()
statement.

The solution is to add
std::cin.ignore();
immediately after the first
std::cin
statement. This will grab a character off of the input buffer (in this case, newline) and discard it.

std::cin.ignore()
can be called three different ways:

No arguments: A single character is taken from the input buffer and discarded:
std::cin.ignore(); //discard 1 character


One argument: The number of characters specified are taken from the input buffer and discarded:
std::cin.ignore(33); //discard 33 characters


Two arguments: discard the number of characters specified, or discard characters up to and including the specified delimiter (whichever comes first):
std::cin.ignore(26, '/n'); //ignore 26 characters or to a newline, whichever comes first


If std::cin is presented with input it cannot process, std::cin goes into a "fail" state

The input it cannot process is left on the input stream.

All input will be ignored by std::cin until the "fail" state is cleared:
std::cin.clear()


A routine that reads a number directly should:
Read in the number

Check to see that the input stream is still valid

If the input stream is not good (
!std::cin
)
Call
std::cin.clear()
to take the stream out of the "fail" state.

Remove from the stream the input that caused the problem:
std::cin.ignore(...)


Get the input again if appropriate or otherwise handle the error

Inputing numbers directly, version 1:

#include<limits> //for numeric_limits
float fl;
int bad_input;
do{
bad_input=0;
std::cin >> fl;
if(!std::cin)
{
bad_input=1;
std::cin.clear();
std::cin.ignore(std::numeric_limits<streamsize>::max(),'/n');
}

}while(bad_input);

Inputing numbers directly, version 2:

#include<limits> //for numeric_limits
float fl;
while(!(std::cin >> fl))
{
std::cin.clear();
std::cin.ignore(std::numeric_limits<streamsize>::max(),'/n');
}

A note on limits. If your compiler doesn't support std::numeric_limits<streamsize>::max(), an alternative is to use the c-style method for determining the maximum integer allowed:

#include<climits>
...
std::cin.ignore(INT_MAX, '/n');

#include <cstdlib>
...
int i;
float fl;
char temp[100];

std::cin.getline(temp, 100);
fl=strtof(temp,0);
std::cin.getline(temp, 100);
i=strtol(temp,0,10);


getline will read both strings and numbers without going into a "fail" state.

Include cstdlib to use the converter functions: string-to-long-integer (strtol), string-to-double (strtod), string-to-float (strtof), and string-to-long-double (strtold). Refer to a reference for more information on the second (and third for strtol) arguments to these converter functions.

std::ifstream someVarName("data.txt");
float fl;
char temp[100];
someVarName.getline(temp, 100);
fl=strtof(temp);
int i;
someVarName >> i;

std::ifstream inf("data.txt");
char temp[100];
while(!inf.getline(temp, 100).eof())
{
//process the line
}


the loop will exit once the end of the file is reached

char temp[100];
std::cin.getline(temp, 100, '|');


If only two arguments are supplied to getline, getline will stop at the end of the line (at the newline character).

If three arguments are supplied to getline, getline will stop at the character designated by the third argument.

The stop character is not copied to the string.

The stop character is "eaten" (removed from the input stream).

Given data file:

John|83|52.2
swimming|Jefferson
Jane|26|10.09
sprinting|San Marin

Process using:

std::ifstream inf("data.txt");
char name[30];
while(!inf.getline(name, 30, '|').eof())
{
Athlete* ap;
char jersey_number[10];
char best_time[10];
char sport[40];
char high_school[40];
inf.getline(jersey_number, 10, '|'); #read thru pipe
inf.getline(best_time, 10);          #read thru newline
inf.getline(sport, 40, '|');         #read thru pipe
inf.getline(high_school, 40);        #read thru newline
ap = new Athlete(name, strtod(number), strtof(best_time), sport, high_school);
//do something with ap

}


In a delimited file, only the first field should be in the while loop

For each field: If the field is the last field in the line or the only field in the line, be sure that getline stops at a newline and not some other delimiter

All of the previous examples have assumed that C-style strings (null-terminated character arrays) were being used. C++ provides a string class that, when combined with a particular "getline" function, can dynamically resize to accommodate user input. In general, C++ strings are preferred over C strings.

Here is the same code shown above, this time using C++ strings:

#include <string>
std::ifstream inf("data.txt");
string name;
while(!std::getline(inf, name, '|').eof())
{
Athlete* ap;
std::string jersey_number;
std::string best_time;
std::string sport;
string high_school;
std::getline(inf, jersey_number, '|'); #read thru pipe
std::getline(inf, best_time);          #read thru newline
std::getline(inf, sport, '|');         #read thru pipe
std::getline(inf, high_school);        #read thru newline
ap = new Athlete(name, strtod(number.c_str()),
strtof(best_time.c_str()), sport, high_school);
//do something with ap

}


std::cout.setf(ios::fixed, ios::floatfield);
std::cout.setf(ios::showpoint);
std::cout.precision(2);

Given:
int one=4, two=44;


std::cout << one << std::endl.;
//output:  "4"

std::cout << setw(2) << one << std::endl.;
//output:  " 4"

std::cout.fill('X');
std::cout << setw(2) << one << std::endl.;
//output:  "X4"

std::cout.fill('X');
std::cout << setw(2) << two << std::endl.;
//output:  "44"


The default fill character is a space.

A common fill character when printing numbers is zero "0".
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