Oracle分析函数八——CUBE,ROLLUP
2009-10-22 11:39
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原创于2009年08月02日,2009年10月22日迁移至此。
Oracle
分析函数——CUBE
,
ROLLUP
CUBE
功能描述:
注意:
ROLLUP
功能描述:
注意:
如果是
ROLLUP(A, B, C)
的话,
GROUP BY
顺序
(A
、
B
、
C)
(A
、
B)
(A)
最后对全表进行
GROUP BY
操作。
如果是
GROUP BY CUBE(A, B,
C)
,
GROUP BY
顺序
(A
、
B
、
C)
(A
、
B)
(A
、
C)
(A)
,
(B
、
C)
(B)
(C)
,
最后对全表进行
GROUP BY
操作。
CREATE TABLE studentscore
(
student_name varchar2(20),
subjects varchar2(20),
score number
)
INSERT INTO studentscore
VALUES('WBQ','ENGLISH',90);
INSERT INTO studentscore
VALUES('WBQ','MATHS',95);
INSERT INTO studentscore
VALUES('WBQ','CHINESE',88);
INSERT INTO studentscore
VALUES('CZH','ENGLISH',80);
INSERT INTO studentscore VALUES('CZH','MATHS',90);
INSERT INTO studentscore
VALUES('CZH','HISTORY',92);
INSERT INTO studentscore
VALUES('CB','POLITICS',70);
INSERT INTO studentscore
VALUES('CB','HISTORY',75);
INSERT INTO studentscore
VALUES('LDH','POLITICS',80);
INSERT INTO studentscore
VALUES('LDH','CHINESE',90);
INSERT INTO studentscore
VALUES('LDH','HISTORY',95);
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects);
等同于以下标准
SQL
SELECT NULL,subjects,SUM(score)
FROM studentscore
GROUP BY subjects
UNION
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects);
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1;
SELECT
grouping(student_name),
grouping(subjects),
CASE WHEN grouping(student_name)=0 AND grouping(subjects)=1 THEN '
学生成绩合计
'
WHEN grouping(student_name)=1 AND grouping(subjects)=0 THEN '
课目成绩合计
'
WHEN grouping(student_name)=1 AND grouping(subjects)=1 THEN '
总
计
'
ELSE ''
END
SUMMARY,
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
Oracle
分析函数——CUBE
,
ROLLUP
CUBE
功能描述:
注意:
ROLLUP
功能描述:
注意:
如果是
ROLLUP(A, B, C)
的话,
GROUP BY
顺序
(A
、
B
、
C)
(A
、
B)
(A)
最后对全表进行
GROUP BY
操作。
如果是
GROUP BY CUBE(A, B,
C)
,
GROUP BY
顺序
(A
、
B
、
C)
(A
、
B)
(A
、
C)
(A)
,
(B
、
C)
(B)
(C)
,
最后对全表进行
GROUP BY
操作。
CREATE TABLE studentscore
(
student_name varchar2(20),
subjects varchar2(20),
score number
)
INSERT INTO studentscore
VALUES('WBQ','ENGLISH',90);
INSERT INTO studentscore
VALUES('WBQ','MATHS',95);
INSERT INTO studentscore
VALUES('WBQ','CHINESE',88);
INSERT INTO studentscore
VALUES('CZH','ENGLISH',80);
INSERT INTO studentscore VALUES('CZH','MATHS',90);
INSERT INTO studentscore
VALUES('CZH','HISTORY',92);
INSERT INTO studentscore
VALUES('CB','POLITICS',70);
INSERT INTO studentscore
VALUES('CB','HISTORY',75);
INSERT INTO studentscore
VALUES('LDH','POLITICS',80);
INSERT INTO studentscore
VALUES('LDH','CHINESE',90);
INSERT INTO studentscore
VALUES('LDH','HISTORY',95);
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects);
等同于以下标准
SQL
SELECT NULL,subjects,SUM(score)
FROM studentscore
GROUP BY subjects
UNION
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects);
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1;
SELECT
grouping(student_name),
grouping(subjects),
CASE WHEN grouping(student_name)=0 AND grouping(subjects)=1 THEN '
学生成绩合计
'
WHEN grouping(student_name)=1 AND grouping(subjects)=0 THEN '
课目成绩合计
'
WHEN grouping(student_name)=1 AND grouping(subjects)=1 THEN '
总
计
'
ELSE ''
END
SUMMARY,
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
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