Think in java 答案_Chapter 4_Exercise 5
2007-01-22 14:10
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阅前声明: http://blog.csdn.net/heimaoxiaozi/archive/2007/01/19/1487884.aspx
/****************** Exercise 5 ******************
* Create an array of String objects and assign a
* string to each element. Print the array using
* a for loop.
***********************************************/
public class E05_StringArray {
public static void main(String args[]) {
// Doing it the hard way:
String sa1[] = new String[4];
sa1[0] = "These";
sa1[1] = "are";
sa1[2] = "some";
sa1[3] = "strings";
for(int i = 0; i < sa1.length; i++)
System.out.println(sa1[i]);
// Using aggregate initialization to
// make it easier:
String sa2[] = {
"These", "are", "some", "strings"
};
for(int i = 0; i < sa2.length; i++)
System.out.println(sa2[i]);
}
}
//+M java E05_StringArray
**The above solution shows both ways you can do it: explicitly creating the array object and assigning a string into each slot by hand, or using aggregate initialization, which creates the array object and does the initialization for you.
/****************** Exercise 5 ******************
* Create an array of String objects and assign a
* string to each element. Print the array using
* a for loop.
***********************************************/
public class E05_StringArray {
public static void main(String args[]) {
// Doing it the hard way:
String sa1[] = new String[4];
sa1[0] = "These";
sa1[1] = "are";
sa1[2] = "some";
sa1[3] = "strings";
for(int i = 0; i < sa1.length; i++)
System.out.println(sa1[i]);
// Using aggregate initialization to
// make it easier:
String sa2[] = {
"These", "are", "some", "strings"
};
for(int i = 0; i < sa2.length; i++)
System.out.println(sa2[i]);
}
}
//+M java E05_StringArray
**The above solution shows both ways you can do it: explicitly creating the array object and assigning a string into each slot by hand, or using aggregate initialization, which creates the array object and does the initialization for you.
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