如何判断数据库中1个表已经存在，这样不会重复创建一个新表（用sql语句）

create Table #tempTable
(
ID int IDENTITY PRIMARY KEY,
bookId int,
bookName varchar(50)
)
go
declare @a int
set @a=(select count(*) as 'aa' from sysobjects where name = '#tempTable')
select @a as 'aaaaaa'
结果为了，临时表是始终为0的

在SQL中判断一个表是否存在

<%sql="if exists (select * from sysobjects where id = object_id(N'[dbo].[phone]') and OBJECTPROPERTY(id, N'IsUserTable') = 1) drop table [dbo].[phone]"
con.execute(sql)
%>
如果表phone存在则删除phone表
其中phone是表名,con是connection对像

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对一个表导出其脚本，里面有例子

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SELECT count(*) <br/> FROM sysobjects <br/> WHERE name = 'jqwm'

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<br/> SELECT count(*) <br/> FROM sysobjects <br/> WHERE name = 'yourtablename' <br/> <br/>

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select count(*) from sysobjects where name = "tablename' and type ='U' <br/> count(*)>=1表示存在

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select count(*) from sysobjects where name = "tablename' and type ='U' <br/> count(*)>=1表示存在 <br/> 或者如IronPromises(铁诺)　的方法,本质上一回事

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同意楼上的 <br/>

SELECT Count(*) AS Qty
FROM MSysObjects
WHERE (((MSysObjects.Name) Like 需判断的已知表名));