SQL交叉表实例

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SQL交叉表实例<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />

很简单的一个东西，见网上好多朋友问“怎么实现交叉表？”，以下是我写的一个例子，数据库基于SQL SERVER 2000。

-- ======================================================

--交叉表实例

-- ======================================================

建表：

在查询分析器里运行：

CREATE TABLE [Test] (

 [id] [int] IDENTITY (1, 1) NOT NULL ,

 [name] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,

 [subject] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,

 [Source] [numeric](18, 0) NULL

) ON [PRIMARY]

GO
INSERT INTO [test] ([name],[subject],[Source]) values (N'张三',N'语文',60)
INSERT INTO [test] ([name],[subject],[Source]) values (N'李四',N'数学',70)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'英语',80)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'数学',75)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'语文',57)
INSERT INTO [test] ([name],[subject],[Source]) values (N'李四',N'语文',80)
INSERT INTO [test] ([name],[subject],[Source]) values (N'张三',N'英语',100)
Go

<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" />


交叉表语句的实现：

--用于：交叉表的列数是确定的

select name,sum(case subject when '数学' then source else 0 end) as '数学',

sum(case subject when '英语' then source else 0 end) as '英语',

sum(case subject when '语文' then source else 0 end) as '语文'

from test

group by name

--用于：交叉表的列数是不确定的

declare @sql varchar(8000)
set @sql = 'select name,'

select @sql = @sql + 'sum(case subject when '''+subject+'''
then source else 0 end) as '''+subject+''','
from (select distinct subject from test) as a

select @sql = left(@sql,len(@sql)-1) + ' from test group by name'
exec(@sql)
go

运行结果：